4.9x^2+47x-250=0

Solution for 4.9x^2+47x-250=0 equation:

4.9x^2+47x-250=0

a = 4.9; b = 47; c = -250;
Δ = b2-4ac
Δ = 472-4·4.9·(-250)
Δ = 7109
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-\sqrt{7109}}{2*4.9}=\frac{-47-\sqrt{7109}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+\sqrt{7109}}{2*4.9}=\frac{-47+\sqrt{7109}}{9.8}
$